FTCE General Knowledge Math Practice Test 2026 – All-in-One Guide to Ensure Exam Success!

To determine how many combinations can be formed with \( n = 6 \) and \( r = 2 \), you can use the combinations formula, which is given by:

\[

C(n, r) = \frac{n!}{r!(n - r)!}

\]

In this case:

- \( n \) represents the total number of items, which is 6.

- \( r \) represents the number of items to choose, which is 2.

Substituting the values into the formula, we get:

\[

C(6, 2) = \frac{6!}{2!(6 - 2)!}

\]

\[

= \frac{6!}{2! \cdot 4!}

\]

Now, let's break down \( 6! \):

\[

6! = 6 \times 5 \times 4!

\]

So the calculation simplifies to:

\[

C(6, 2) = \frac{6 \times 5 \times 4!}{2! \times 4!}

\]

The \( 4! \) in the numerator and denominator cancels out:

\[

= \frac{6 \times